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BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    Equal volumes of \[0.02M\] \[CaC{{l}_{2}}\] and \[0.0004M\] \[N{{a}_{2}}S{{O}_{4}}\] are mixed. If \[{{K}_{sp}}\] for \[CaS{{O}_{4}}=2.4\times {{10}^{-5}},\], whether there would be any precipitation ?

    A)  Yes                                       

    B)  No

    C)  Unpredictable                 

    D)  None of these

    Correct Answer: B

    Solution :

                    Let V ml. of each \[CaC{{l}_{2}}\] and \[N{{a}_{2}}S{{O}_{4}}\] are mixed. \[\underset{0.02V}{\mathop{CaC{{l}_{2}}}}\,+\underset{0.0004V}{\mathop{N{{a}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}\underset{0}{\mathop{CaS{{O}_{4}}}}\,+\underset{0}{\mathop{2NaCl}}\,\]                 \[[C{{a}^{2+}}]=\frac{0.02V}{2V}=0.01\]                 \[[S{{O}_{4}}^{2-}]=\frac{0.0004V}{2V}=0.0002\]                 \[[C{{a}^{2+}}][S{{O}_{4}}^{2-}]=0.01\times 0.0002\]                 \[=2\times {{10}^{-6}}\] Since solubility product \[2.4\times {{10}^{-5}}\] is greater than ionic product \[2\times {{10}^{-6}},\], \[CaS{{O}_{4}}\] will not be precipitated.


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