A) Yes
B) No
C) Unpredictable
D) None of these
Correct Answer: B
Solution :
Let V ml. of each \[CaC{{l}_{2}}\] and \[N{{a}_{2}}S{{O}_{4}}\] are mixed. \[\underset{0.02V}{\mathop{CaC{{l}_{2}}}}\,+\underset{0.0004V}{\mathop{N{{a}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}\underset{0}{\mathop{CaS{{O}_{4}}}}\,+\underset{0}{\mathop{2NaCl}}\,\] \[[C{{a}^{2+}}]=\frac{0.02V}{2V}=0.01\] \[[S{{O}_{4}}^{2-}]=\frac{0.0004V}{2V}=0.0002\] \[[C{{a}^{2+}}][S{{O}_{4}}^{2-}]=0.01\times 0.0002\] \[=2\times {{10}^{-6}}\] Since solubility product \[2.4\times {{10}^{-5}}\] is greater than ionic product \[2\times {{10}^{-6}},\], \[CaS{{O}_{4}}\] will not be precipitated.You need to login to perform this action.
You will be redirected in
3 sec