A) 7
B) 14
C) 28
D) 24
Correct Answer: B
Solution :
\[\underset{At\,equil\,0.08}{\mathop{2NO(g)}}\,+\underset{0.64}{\mathop{{{O}_{2}}(g)}}\,\underset{0.12}{\mathop{2N{{O}_{2}}(g)}}\,,\,\,V=4litre\] \[{{K}_{c}}=\frac{{{[N{{O}_{2}}]}^{2}}}{{{[NO]}^{2}}\,[{{O}_{2}}]}\] \[=\frac{{{\left( \frac{0.12}{4} \right)}^{2}}}{{{\left( \frac{0.08}{4} \right)}^{2}}\times \left( \frac{0.64}{4} \right)}\] \[=\frac{0.12\times 0.12\times 4}{0.08\times 0.08\times 0.64}=14.06\]You need to login to perform this action.
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