A) 3\[\Omega \]
B) 2\[\Omega \]
C) 4\[\Omega \]
D) emf of a cell is required to final the value of X.
Correct Answer: B
Solution :
Equivalent resistance of \[{{R}_{1}}\] and \[{{R}_{2}}\]. \[P={{R}_{1}}+{{R}_{2}}=12+4=16\Omega \] Equivalent resistance of \[{{R}_{3}}\] and \[{{R}_{4}}\] \[Q=1+3=4\Omega \] Equivalent resistance of \[{{R}_{5}}\] and \[{{R}_{6}}\] \[R=\frac{1\times 1}{1+1}=\frac{1}{2}\Omega \] For no current in arm BD, bridge should be balanced. \[\frac{P}{Q}=\frac{R}{S}\] \[\frac{16}{X}=\frac{4}{1/2}\] \[\frac{16}{X}=8\] \[\Rightarrow \] \[X=2\Omega \]
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