A) 900 MW
B) 450 W
C) 200 MW
D) 500 W
Correct Answer: A
Solution :
Power of reactor \[=\frac{E}{t}\] \[=\frac{m{{c}^{2}}}{t}\] \[=\frac{0.01\times {{10}^{-6}}\times {{(3\times {{10}^{8}})}^{2}}}{1}\] \[=1\times {{10}^{-8}}\times 9\times {{10}^{16}}\] \[=9\times {{10}^{8}}\] \[=900\times {{10}^{6}}W\] \[=900MW\]You need to login to perform this action.
You will be redirected in
3 sec