A) 3
B) 2
C) 4
D) 0
Correct Answer: A
Solution :
\[Cr\] (atomic number = 24) \[=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{5}},4{{s}^{1}}\] \[C{{r}^{+3}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{3}}\] Thus, number of unpaired electrons = 3You need to login to perform this action.
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