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BVP Medical BVP Medical Solved Paper-2002

  • question_answer
    The total number of unpaired electrons in \[C{{r}^{+3}}\] ion are:

    A)  3                                            

    B)  2

    C)  4                                            

    D)  0

    Correct Answer: A

    Solution :

                    \[Cr\] (atomic number = 24) \[=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{5}},4{{s}^{1}}\] \[C{{r}^{+3}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{3}}\] Thus, number of unpaired electrons = 3


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