BVP Medical BVP Medical Solved Paper-2002

  • question_answer
    The momentum for the radiation of wavelength 0.33 nm is :

    A)  \[3.56\times {{10}^{-16}}\]        

    B)  \[4.32\times {{10}^{22}}\]

    C)  \[2.01\times {{10}^{-24}}\]        

    D)  \[3.12\times {{10}^{-28}}\]

    Correct Answer: C

    Solution :

                    According to de Broglie equation, \[\lambda =\frac{h}{p}\] where, p = momentum of electron \[\therefore \] \[p=\frac{h}{\lambda }=\frac{6.625\times {{10}^{-34}}}{0.33\times {{10}^{-9}}}\]\[=2.01\times {{10}^{-24}}kg\,m/\sec \]


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