A) \[0.64g\]
B) \[1.24g\]
C) \[1.78g\]
D) \[0.79g\]
Correct Answer: D
Solution :
Milli equivalents of \[KMn{{O}_{4}}\] solution \[=\frac{1}{10}\times 250=25\] Equivalents of \[KMn{{O}_{4}}=\frac{25}{1000}=0.025\] Thus, required weight = number of equivalents \[\times \] equivalent weight. \[=0.025\times 31.6\] \[=0.79g\]You need to login to perform this action.
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