question_answer

1-phenyl ethanol can be prepared by the reaction of \[{{C}_{6}}{{H}_{5}}CHO\] with :

A)  \[C{{H}_{3}}I+Mg\]

B)  \[{{C}_{2}}{{H}_{5}}Br+{{H}_{2}}O\]

C)  \[C{{H}_{3}}C{{H}_{2}}Br+Alc.KOH\]

D)  \[C{{H}_{3}}Br=A{{l}_{4}}{{C}_{3}}\]

Correct Answer: A

Solution :

                  \[\underset{\begin{smallmatrix}  Methyl\,magnesium\,iodide \\  (Grignard\,reagent) \end{smallmatrix}}{\mathop{C{{H}_{3}}I+Mg\xrightarrow[ether]{Dry}C{{H}_{3}}MgI}}\,\]