A) momentum
B) angular momentum
C) work
D) pressure
Correct Answer: B
Solution :
Angular momentum \[=m\upsilon r\] \[\text{=kilogram }\!\!\times\!\!\text{ }\frac{\text{metre}}{\text{second}}\text{ }\!\!\times\!\!\text{ metre}\] \[\text{=kilogram }\!\!\times\!\!\text{ }\frac{{{\text{(metre)}}^{\text{2}}}\text{ }\!\!\times\!\!\text{ second}}{\text{second }\!\!\times\!\!\text{ second}}\] \[=\left( kg\times \frac{metre}{{{\sec }^{2}}} \right)\times \sec \] \[=joule\times \sec \]
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