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BVP Medical BVP Medical Solved Paper-2003

  • question_answer
    When \[_{92}{{U}^{235}}\]undergoes fission, 0.1% its original mass is changed into energy. How much energy is released if 1 kg of\[_{92}{{U}^{235}}\] undergoes fission?

    A) \[9\times {{10}^{10}}J\]                

    B) \[9\times {{10}^{11}}J\]

    C)  \[9\times {{10}^{12}}J\]                              

    D) \[9\times {{10}^{13}}J\]

    Correct Answer: D

    Solution :

                    From the mass energy equivalence of Einstein \[E=\Delta m{{c}^{2}}\] Here:   \[\Delta m=\frac{0.1}{100}={{10}^{-3}}kg\] So,   \[E={{10}^{-3}}\times {{(3\times {{10}^{8}})}^{2}}=9\times {{10}^{13}}J\]


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