BVP Medical BVP Medical Solved Paper-2003

  • question_answer
    Ultraviolet radiation of 6.2 eV falls on an aluminium foil surface. Work function is 4.2 eV. The K.E. of the fastest electron emitted approximately :

    A) \[3.2\times {{10}^{-21}}J\]                          

    B) \[3.2\times {{10}^{-19}}J\]

    C)  \[3.2\times {{10}^{-15}}J\]                         

    D) \[3.2\times {{10}^{-17}}J\]

    Correct Answer: B

    Solution :

                    Using the relation \[KE=hv-{{\omega }_{0}}\] \[KE=6.2-4.2=2eV\] \[=2\times 1.6\times {{10}^{-19}}=3.2\times {{10}^{-19}}J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner