BVP Medical BVP Medical Solved Paper-2003

  • question_answer
    A 30 g bullet travelling initially at 500 m/s penetrates 12 cm in to wooden block. The average force exerted will be :

    A)  31250 N                              

    B)  41250 N

    C)  31750 N                              

    D)  30450 N

    Correct Answer: A

    Solution :

                    From kinetic energy relation \[\frac{1}{2}m{{\upsilon }^{2}}=F.s\]                 or            \[F=\frac{m{{\upsilon }^{2}}}{2s}\]                                 \[=\frac{30\times {{10}^{-3}}\times {{(500)}^{2}}}{2\times 12\times {{10}^{-2}}}\]                                 \[=31250N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner