A) \[1.28\times {{10}^{14}}N,1.1\times {{10}^{-3}}m\]
B) \[1.28\times {{10}^{15}}N,1.2\times {{10}^{-12}}m\]
C) \[1.28\times {{10}^{-13}}N,1.1\times {{10}^{-4}}m\]
D) none of these
Correct Answer: C
Solution :
Force produced on an electron is given by \[F=e\upsilon B=1.6\times {{10}^{-19}}\times 4\times {{10}^{6}}\times 2\times {{10}^{-1}}\] \[=1.28\times {{10}^{-13}}N\] Since electron is moving in circular orbit So, \[\frac{m{{\upsilon }^{2}}}{r}=e\upsilon B\] or \[r=\frac{m\upsilon }{eB}=\frac{9\times {{10}^{-31}}\times 4\times {{10}^{6}}}{1.6\times {{10}^{-19}}\times 2\times {{10}^{-1}}}\] \[=1.1\times {{10}^{-4}}m\]
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