BVP Medical BVP Medical Solved Paper-2003

  • question_answer
    A cyclic hydrocarbon molecule has all the carbon and hydrogen in a single plane. All the carbon-carbon bonds are of same length, less then \[1.54\overset{\text{o}}{\mathop{\text{A}}}\,\], but more than \[1.34\overset{\text{o}}{\mathop{\text{A}}}\,\]. The \[C-C\] bond angle will be:

    A)  \[{{109}^{o}}28\]            

    B)  \[{{100}^{o}}\]

    C)  \[{{180}^{o}}\]                                

    D)  \[{{120}^{o}}\]

    Correct Answer: D

    Solution :

                    Cyclic hydrocarbon, with-carbon-carbon bond length between\[1.34\overset{\text{o}}{\mathop{\text{A}}}\,\] and \[1.54\overset{\text{o}}{\mathop{\text{A}}}\,\], is benzene in which due to resonance, \[C-C\] bond length is \[1.39\overset{\text{o}}{\mathop{\text{A}}}\,\] (i.e., between \[1.34\overset{\text{o}}{\mathop{\text{A}}}\,-1.54\overset{\text{o}}{\mathop{\text{A}}}\,\]). Benzene is a hexagonal molecule with bond-angle equal to \[{{120}^{o}}\].


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