A) \[9.6kg\]
B) \[96.0\text{ }kg\]
C) \[6.4kg\]
D) \[2.8kg\]
Correct Answer: A
Solution :
\[\underset{12\times 2+4=28}{\mathop{{{C}_{2}}{{H}_{4}}}}\,+\underset{96}{\mathop{3{{O}_{2}}}}\,\xrightarrow{{}}2C{{O}_{2}}+2{{H}_{2}}O\] \[\because \] The weight of oxygen required for complete combustion of 28 g ethylene \[=96g\] \[\therefore \] Weight of oxygen required for combustion of 2.8 kg ethylene \[=\frac{96\times 2.8\times 1000}{28\times 1000}kg\] \[=9.6kg\]
You need to login to perform this action.
You will be redirected in
3 sec
