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BVP Medical BVP Medical Solved Paper-2003

  • question_answer
    The equilibrium constant  \[{{K}_{p}}\]for the reaction, \[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\] is:

    A)  more than one

    B)  less than one

    C)  equal to \[{{K}_{C}}\]

    D)  zero

    Correct Answer: C

    Solution :

                     \[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\] We know that, \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] here, \[\Delta {{n}_{g}}=2-2=0\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{0}}={{K}_{c}}\]


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