A) \[0.72,0.71\]
B) \[0.72,1.6\]
C) \[1.6,1.58\]
D) \[0.71,0.72\]
Correct Answer: B
Solution :
Atomic radii decrease in a period from left to right, hence fluorine has a very less atomic radii (covalent atomic radii \[=0.72\overset{\text{o}}{\mathop{\text{A}}}\,\]). But inert gases (like Ne) are monoatomic gases, hence their covalent atomic radii cannot be found out. In fact, their calculated atomic radii is the van der Waal radii, which is found almost double to covalent radii, hence the van der Waal radius of neon (Ne) is about \[1.60\overset{\text{o}}{\mathop{\text{A}}}\,\].
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