A) \[4.2\times {{10}^{3}}N\]
B) \[5.2\times {{10}^{3}}N\]
C) \[{{10}^{2}}\]
D) \[{{10}^{-2}}\]
Correct Answer: C
Solution :
The frequency of light rays remains unchanged when it passes through one medium to another medium. Therefore the frequency of ray will be \[{{\tan }^{-1}}\left( \frac{1}{5} \right)\] Hz.You need to login to perform this action.
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