A) 1.88 m/s, 35.5 m/\[I=100\sin 200\pi t\], 35.5 N
B) 2.88 m/s, 45.5 m/\[\frac{1}{400}s\], 45.5N
C) 3.88 m/s, 55.5 m/\[\frac{1}{300}s\], 55.5N
D) none of these
Correct Answer: A
Solution :
Here: mass of the body = 1 kg Radius of circle = 0.1 m n = 3 rev/sec Hence, angular speed \[\omega =2\pi \times 3=6\pi \,rad/\sec \] (1) linear speed \[\upsilon =r\omega =0.1\times 6\times 3.14=1.88m/s\] (2) acceleration \[a=r{{\omega }^{2}}=0.1\times {{(6\pi )}^{2}}=35.5m/{{s}^{2}}\] (3) tension in strip \[T=mr{{\omega }^{2}}=1\times 0.1\times {{(6\pi )}^{2}}=35.5N\]You need to login to perform this action.
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