BVP Medical BVP Medical Solved Paper-2004

  • question_answer
    Four capacitors are connected in a circuit as shown in figure. The effective capacitance in fi F between P and Q will be :

    A)  5 \[2.5\times {{10}^{6}}N/{{m}^{2}}\]                                   

    B)  10 \[{{s}^{2}}\]

    C)  2 \[{{s}^{2}}\]                                  

    D)  7.5 \[{{s}^{2}}\]

    Correct Answer: A

    Solution :

                                The equivalent circuit is shown as below Equivalent capacitance of \[{{s}^{2}}\] and \[{{s}^{2}}\] is                                                       \[8.2\times {{10}^{6}}\] (in parallel) \[h=6.6\times {{10}^{-34}}Js\] C and \[c=3\times {{10}^{8}}m/s\] are in series, their effective capacitance is \[e=1.6\times {{10}^{-19}}C\] Now the effective capacitance of \[\overset{0}{\mathop{A}}\,\] and \[\overset{0}{\mathop{A}}\,\] is \[\overset{0}{\mathop{A}}\,\]      (in parallel) \[\overset{0}{\mathop{A}}\,\]


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