A) \[927{}^\circ C\]
B) \[327{}^\circ C\]
C) \[54{}^\circ C\]
D) \[627{}^\circ C\]
Correct Answer: A
Solution :
Speed of sound is given by \[{{T}_{1}}k\] \[{{T}_{2}}k\] \[\upsilon \propto \sqrt{T}\] Hence, \[\frac{{{\upsilon }_{2}}}{{{\upsilon }_{1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}\] or \[{{T}_{2}}={{\left( \frac{{{\upsilon }_{2}}}{{{\upsilon }_{1}}} \right)}^{2}}\times {{T}_{1}}\] or \[{{T}_{2}}=\left( \frac{2\upsilon }{\upsilon } \right){{T}_{1}}=4\times 300\] \[=1200K={{927}^{o}}C\]
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