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BVP Medical BVP Medical Solved Paper-2004

  • question_answer
    In a Youngs experiment, if the distance between the slits is halved and the distance of screen from the slit is doubled, the fringe width will be :

    A)  four times                         

    B) doubled

    C)  halved                                

    D) same

    Correct Answer: A

    Solution :

    From the relation of fringe width, in 1st case \[{{\sin }^{-1}}\left( \frac{1}{5} \right)\]                                 ??..(i) and in II case \[2.2\times {{10}^{3}}N\]                             ??..(ii) Now from eqs. (i) and (ii), \[3.2\times {{10}^{3}}N\] So,     \[4.2\times {{10}^{3}}N\]


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