A) \[\Omega \]
B) \[\Omega \]
C) \[\Omega \]
D) \[\Omega \]
Correct Answer: A
Solution :
Here: \[E=10\times {{10}^{5}}kWh\] \[={{10}^{6}}\times 3.6\times {{10}^{6}}J=3.6\times {{10}^{12}}J\] (\[\because \] \[1\,k\,Wh=3.6\times {{10}^{6}}J\]) Now from Einsteins mass energy equivalence relation \[E=\Delta m{{c}^{2}}\] or \[\Delta m=\frac{E}{{{c}^{2}}}=\frac{3.6\times {{10}^{12}}}{{{(3\times {{10}^{8}})}^{2}}}=4\times {{10}^{-5}}kg\]
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