A) \[{{C}_{3}}{{H}_{5}}{{O}_{3}}\]
B) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
C) \[{{C}_{3}}{{H}_{10}}{{O}_{5}}\]
D) \[{{C}_{3}}{{H}_{4}}{{O}_{3}}\]
Correct Answer: B
Solution :
\[\because \] 0.833 mol. of carbohydrate has hydrogen = 10 g \[\therefore \]1 mol of carbohydrate has hydrogen \[=\frac{10\times 1}{0.833}\] \[=12g\] Empirical formula of hydrocarbon \[(C{{H}_{2}}O)\] contain 2g. hydrogen per mole. Hence, molecular formula should contain hydrogen atoms \[=\frac{12}{2}\times 2=12\] \[\therefore \] molecular formula of hydrocarbon \[={{C}_{6}}{{H}_{12}}{{O}_{6}}\]
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