A) \[6.8\times {{10}^{-6}}\]
B) \[6.8\times {{10}^{6}}\]
C) \[2.2\times {{10}^{-9}}\]
D) none of these
Correct Answer: D
Solution :
\[\underset{s\,\,mol/litre}{\mathop{Pb{{I}_{2}}}}\,\underset{s}{\mathop{P{{b}^{2+}}}}\,+\underset{2s}{\mathop{2{{I}^{-}}}}\,\] \[\therefore \] \[{{K}_{sp}}=[P{{b}^{2+}}]{{[{{I}^{-}}]}^{2}}\] \[=(s){{(2s)}^{2}}\] \[=4{{s}^{3}}\] Given, that s = 0.005 mot/litre \[\therefore \] \[{{K}_{sp}}=4{{(0.005)}^{3}}\] \[=5.00\times {{10}^{-7}}\]
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