A) cone. \[HN{{O}_{3}}\]+ cone. \[{{H}_{2}}S{{O}_{4}}\]
B) cone. \[HN{{O}_{3}}\]
C) cone. \[{{H}_{2}}S{{O}_{4}}\]+ fuming \[HN{{O}_{3}}\]
D) \[KN{{O}_{2}}\]
Correct Answer: A
Solution :
Benzene is nitrated in presence of cone. \[HN{{O}_{3}}\]and cone. \[{{H}_{2}}S{{O}_{4}}\],both. When an activating group (like, \[-C{{H}_{3}}-OH\]) is present in benzene ring, than it can be nitrated only by cone. \[HN{{O}_{3}}\] .
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