A) \[0%\]
B) \[100%\]
C) \[75%\]
D) \[50%\]
Correct Answer: A
Solution :
\[\Delta T=\frac{1000\times 1.86\times 20}{m\times 500}\] \[0.74=\frac{1000\times 1.86\times 20}{m\times 500}\] \[m=100\] Actual molecular mass = 100 \[\therefore \]The degree of ionization of the electrolyte is 0%.You need to login to perform this action.
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