A) 2 V, 5 Hz
B) 200 V, 500 Hz
C) 2V, 50 Hz
D) 200 V, 50 Hz
Correct Answer: D
Solution :
Key Idea: The transformation ratio is \[\frac{{{V}_{s}}}{{{V}_{p}}}=\frac{{{N}_{s}}}{{{N}_{p}}}.\] The transformer converts AC high voltage into AC low voltage, but it does not cause any change in frequency. The transformation ratio is given by \[\frac{{{V}_{s}}}{{{V}_{p}}}=\frac{{{N}_{s}}}{{{N}_{p}}}.\] Making substitution, we obtain \[{{V}_{s}}=\frac{{{N}_{s}}}{{{N}_{p}}}\,\,{{V}_{p}}=\frac{5000}{500}\times 20=200V\] Thus, output has voltage 200 V and frequency 50 Hz. NOTE: The efficiency of an ideal transformer is 1 (or 100%). But in practice due to loss in energy, the efficiency of a transformer is always less than 1 (or sless than 100%).
You need to login to perform this action.
You will be redirected in
3 sec
