A) \[2\times {{10}^{-7}}N,\]repulsive
B) \[2\times {{10}^{-7}}N,\]attractive
C) \[2\times {{10}^{-4}}N,\]repulsive
D) \[2\times {{10}^{-4}}N,\]attractive
Correct Answer: D
Solution :
The force per unit length of wire 2 due to wire 1 is, \[\frac{F}{l}=\frac{{{\mu }_{0}}}{2\pi }\frac{{{i}_{1}}{{i}_{2}}}{r}\] Making substitution, we obtain \[\frac{F}{l}=\frac{4\pi \times {{10}^{-7}}}{2\pi }\times \frac{10\times 10}{10\times {{10}^{-2}}}\] \[=2\times {{10}^{-4}}N/m\] Since, currents are flowing in same direction so, force produced between them will be attractive. NOTE: If the currents are flowing in opposite direction, the force between them will be repulsive.You need to login to perform this action.
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