2. Solved Papers
  3. BVP Medical

BVP Medical BVP Medical Solved Paper-2006

  • question_answer
    In a fission reaction \[_{92}^{236}U{{\to }^{117}}X{{+}^{117}}Y+n+n\]the binding energy per nucleon of X and Y is 8.5 MeV whereas of 236U is 7.6 MeV. The total energy liberated will be about:

    A)  2000 MeV                          

    B) 200 MeV

    C)  2 MeV                                 

    D) 200 MeV

    Correct Answer: B

    Solution :

                    Key Idea: The total energy liberated will be the difference between the binding energy of two sides. Binding energy of fashioned nucleus \[=236\times 7.6MeV\] Binding energy of product                 \[=117\times 8.\,\,\,\,+117\times 8.5\]                 \[=2\times 117\times 8.5\] Hence, net binding energy = Binding energy of product - Binding energy of fashioned nucleus                 \[=234\times 8.5-234\times 7.6\]                 \[=1989-1793.6=195.4MeV\]                 \[\approx 200MeV\] Thus, in per fission of uranium nearly \[200MeV\]energy is released. NOTE: The binding energy per nucleon is the measure of stability of a nucleus. Out of the elements available \[F{{e}^{56}}\] is most stable.


You need to login to perform this action.
You will be redirected in 3 sec spinner