A) 2000 MeV
B) 200 MeV
C) 2 MeV
D) 200 MeV
Correct Answer: B
Solution :
Key Idea: The total energy liberated will be the difference between the binding energy of two sides. Binding energy of fashioned nucleus \[=236\times 7.6MeV\] Binding energy of product \[=117\times 8.\,\,\,\,+117\times 8.5\] \[=2\times 117\times 8.5\] Hence, net binding energy = Binding energy of product - Binding energy of fashioned nucleus \[=234\times 8.5-234\times 7.6\] \[=1989-1793.6=195.4MeV\] \[\approx 200MeV\] Thus, in per fission of uranium nearly \[200MeV\]energy is released. NOTE: The binding energy per nucleon is the measure of stability of a nucleus. Out of the elements available \[F{{e}^{56}}\] is most stable.You need to login to perform this action.
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