A) they will never meet
B) x = 10 m
C) x= 5m
D) x = 0
Correct Answer: C
Solution :
If the man pulls the cart by the rope, the man and cart will meet at the centre of mass. \[\therefore \] \[{{x}_{cm}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] \[=\frac{M\times 0+M\times 10}{M+M}\] \[=\frac{10M}{2M}=5m\]You need to login to perform this action.
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