A) first increase and then decrease
B) first decrease and then increase
C) go on increasing
D) go on decreasing
Correct Answer: A
Solution :
Time period of simple pendulum \[T=2\pi \sqrt{\left( \frac{l}{g} \right)}\propto \sqrt{l}\], where \[l\] is effective length. (i.e., distance between centre of suspension and centre of gravity of bob) Initially centre of gravity is at the centre of sphere [Fig. ]. When water leaks the centre of gravity goes down until it is half-filled [Fig. ]; then it begins to go up and finally it again goes at the centre [Fig. ]. That is effective length first increases and then decreases. As \[T\propto \sqrt{l}\], so time period first increases and then decreases.You need to login to perform this action.
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