A) \[{{H}_{2}}Te\]
B) \[{{H}_{2}}Se\]
C) \[{{H}_{2}}S\]
D) \[{{H}_{2}}O\]
Correct Answer: D
Solution :
As we move down the group, the bond angle decrease due to decrease in bond pair-bond pair repulsion. \[Bond\text{ }angle\text{ }\begin{matrix} {{H}_{2}}O \\ {{104.5}^{o}} \\ \end{matrix}\text{ }\begin{matrix} {{H}_{2}}S \\ {{92.2}^{o}} \\ \end{matrix}\text{ }\begin{matrix} {{H}_{2}}Se \\ {{91}^{o}} \\ \end{matrix}\text{ }\begin{matrix} {{H}_{2}}Te \\ {{90}^{o}} \\ \end{matrix}\]
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