Bond | \[({{E}_{diss}})\,(kcal\,-\,mo{{l}^{-1}})\] |
C-A | 240 |
C-B | 382 |
C-D | 276 |
C-E | 486 |
A) E
B) B
C) D
D) A
Correct Answer: A
Solution :
Smaller the atom more effective the overlap would be, consequently larger will be the bond dissociation energy.You need to login to perform this action.
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