A) 1 : 9
B) 9 : 1
C) 3:1
D) 1 : 3
Correct Answer: D
Solution :
For a body mass m moving with velocity v, kinetic energy is \[J=\frac{1}{2}M{{R}^{2}}\omega \] .....(i) Also momentum p= mass (m)x velocity (v)...(ii) squaring Eq. (ii) and readjusting with terms in Eq. (i), we get \[I={{I}_{4}}+m{{R}^{2}}\] Given, \[=\frac{1}{4}m{{R}^{2}}+m{{R}^{2}}=\frac{5}{4}m{{R}^{2}}\] \[g=g\left( 1-\frac{h}{R} \right)\] \[\Rightarrow \]
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