A) 500 V
B) 400 V
C) 300 V
D) 200 V
Correct Answer: B
Solution :
Let the charges on capacitors be \[\frac{16}{5R}\] then \[\frac{16}{7R}\] Total charge \[{{E}_{n}}\] \[4{{E}_{n}}\] Let the equivalent potential be V and since capacitors are connected in parallel their equivalent capacitance is \[{{E}_{n}}/4\] \[2{{E}_{n}}\] \[{{E}_{n}}/2\] \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\] Given, \[\overset{0}{\mathop{A}}\,\] \[K=\frac{1}{2}m{{v}^{2}}\] \[W=\mu ngs\] \[\mu \] \[\frac{1}{2}m{{v}^{2}}=\mu mgs\] Note: Capacitors are combined in parallel when we require a large capacitance to a small potential.You need to login to perform this action.
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