A) \[4938.8\text{ }J\]
B) \[4138.8\text{ }J\]
C) \[5744.1\text{ }J\]
D) \[6257.2\text{ }J\]
Correct Answer: C
Solution :
Key Idea: For calculating work done during isothermal expansion of ideal gas we use the formula, \[W=2.303\text{ }nRT\text{ }log\text{ }\frac{{{P}_{2}}}{{{P}_{1}}}\] W = work done, \[n=1\], \[T=300K,\] \[{{P}_{2}}=1\] atm, \[{{P}_{1}}=10\] atm \[W=2.303\text{ }nRT\text{ }log\text{ }\frac{{{P}_{2}}}{{{P}_{1}}}\] \[=2.303\times 1\times 8.314\times 300\times \log \frac{1}{10}\] \[=5744.1J\]You need to login to perform this action.
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