A) \[{{C}_{2}}{{H}_{4}}\]
B) \[C{{H}_{3}}OH\]
C) \[C{{H}_{3}}Br\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} methyl \\ bromide \end{smallmatrix}}{\mathop{C{{H}_{3}}Br}}\,+{{H}_{2}}\xrightarrow{LiAl{{H}_{4}}}\underset{methane}{\mathop{C{{H}_{4}}}}\,+HBr\] \[\underset{\begin{smallmatrix} methyl \\ bromide \end{smallmatrix}}{\mathop{2C{{H}_{3}}Br}}\,+Na\xrightarrow{{}}\underset{ethane}{\mathop{{{C}_{2}}{{H}_{6}}}}\,+2NaBr\]
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