A) Ethylene glycol
B) Ethylene oxide
C) Ethylene dinitrate
D) Ethane
Correct Answer: A
Solution :
\[\underset{ethylene}{\mathop{{{H}_{2}}C=C{{H}_{2}}}}\,+HOCl\xrightarrow{{}}\underset{ethylene\,chlorohydrin}{\mathop{\underset{Cl}{\mathop{\underset{|}{\mathop{{{H}_{2}}C}}\,}}\,-C{{H}_{2}}OH}}\,\] \[\xrightarrow{NaHC{{O}_{3}}}\underset{ethylene\,glycol}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{{{H}_{2}}C}}\,}}\,-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}}}\,+NaCl+C{{O}_{2}}\]
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