A) 1 : 2
B) 1 : 4
C) 2 : 1
D) 4 : 1
Correct Answer: A
Solution :
Excess pressure inside the bubble, \[p=\frac{4T}{r}\] Then, \[{{p}_{1}}=\frac{4T}{{{r}_{1}}}\] ...?(i) \[{{p}_{2}}=\frac{4T}{{{r}_{2}}}\] ??..(ii) From Eqs. (i) and (ii), we have \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{4T/{{r}_{1}}}{4T/{{r}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{1}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
