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BVP Medical BVP Medical Solved Paper-2008

  • question_answer
    Pure silicon at 300 K has equal electron ne and whole\[({{n}_{h}})\] concentration of\[1.5\times {{10}^{16}}\,\,{{m}^{-3}}\]. Doping by indium increases \[{{n}_{h}}\]to \[\,\,4.5\times {{10}^{22}}\,\,{{m}^{-3}}\]. The \[{{n}_{e}}\] in the doped silicon is

    A) \[9\times {{10}^{5}}\]                   

    B) \[5\times {{10}^{9}}\]

    C) \[2.25\times {{10}^{11}}\]                           

    D) \[3\times {{10}^{19}}\]

    Correct Answer: B

    Solution :

                               \[{{n}_{e}}{{n}_{h}}={{({{n}_{i}})}^{2}}\] \[{{n}_{e}}\times 4.5\times {{10}^{22}}={{(1.5\times {{10}^{16}})}^{2}}\] \[{{n}_{e}}=\frac{2.25\times {{10}^{32}}}{4.5\times {{10}^{22}}}\] \[{{n}_{e}}=5\times {{10}^{9}}\]


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