A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) \[\frac{2}{3}\]
D) \[\frac{3}{4}\]
Correct Answer: D
Solution :
From the relation, \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] ?.(i) \[\frac{n}{2}=\frac{1}{2l}\sqrt{\frac{T}{m}}\] ?..(ii) From Eqs. (i) and (ii), we get \[\frac{T}{T}=\frac{1}{4}\] \[1-\frac{T}{T}=1-\frac{1}{4}\] \[\frac{T-T}{T}=\frac{3}{4}\]
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