A) \[5MeV\]
B) \[7MeV\]
C) \[10MeV\]
D) \[14MeV\]
Correct Answer: B
Solution :
He atom has \[2p+2n\] Hence, \[\Delta m=(2\times 1.0078+2\times 1.0087)-4.0026\] \[=0.0304amu\] \[\therefore \] energy released \[=0.0304\times 931.5\,MeV\] \[=28.3\,MeV\] Binding energy per nucleon \[\underset{(approximately)}{\mathop{=\frac{28.3}{4}=7\,MeV}}\,\]You need to login to perform this action.
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