A) \[KI\]and aq \[KOH\]
B) \[{{I}_{2}}\] and aq \[KOH\]
C) \[{{I}_{2}}\]/ aq \[KI\]
D) \[HI\] and \[HI{{O}_{3}}\]
Correct Answer: B
Solution :
For iodoform reaction, we need an oxidising agent which is provided by only \[{{I}_{2}}/KOH\], i.e., \[I{{O}^{-}}\]ion. Hypoiodide ion first oxidses\[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow{{}}C{{H}_{3}}CHO\]and then brings about iodination of \[C{{H}_{3}}CHO\] to \[{{I}_{3}}C.CHO\]. Alkaline hydrolysis of \[C{{I}_{3}}CHO\] then gives \[CH{{I}_{3}}\]. The other three reagents do not contain any oxidising species and hence, fail to give iodoform test.
You need to login to perform this action.
You will be redirected in
3 sec
