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BVP Medical BVP Medical Solved Paper-2009

  • question_answer
    A motor cycle racer takes a round with speed \[20\text{ }m{{s}^{-1}}\] in a curvature of radius of R = 40 m, then the leaning angle of motor cycle for safe turn is \[(g=10m{{s}^{-2}})\]

    A)  \[20{}^\circ \]                                  

    B) \[30{}^\circ \]

    C)  \[45{}^\circ \]                                  

    D)  \[60{}^\circ \]

    Correct Answer: C

    Solution :

    A motor cyclist provides himself the necessary centripetal force by leaning inward on a horizontal track, while going round a curve. For a safe turn cyclist should bend through an angle \[\theta ={{\tan }^{-1}}\left[ \frac{{{v}^{2}}}{rg} \right]={{\tan }^{-1}}\left[ \frac{{{(20)}^{2}}}{40\times 10} \right]\] \[={{\tan }^{-1}}(1)={{45}^{o}}\]


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