A) \[3p\]
B) \[3d\]
C) \[3s\]
D) Equal
Correct Answer: C
Solution :
The orbital with lower value of \[(n+l)\] has lower energy and is close to the nucleus. Among \[3s(3+0=3),3p(3+1=4)\] and \[3d(3+2=5)\]orbitals, 3s has lower value of \[(n+l)\], thus, it is close to the nucleus and provide a higher probability to the electron of being found close to the nucleus.You need to login to perform this action.
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