A) \[\frac{h}{\sqrt{2mk}}\]
B) \[\frac{h}{k}\]
C) \[\frac{hk}{2mc}\]
D) \[\frac{hc}{2mk}\]
Correct Answer: A
Solution :
According to de-Broglie theory, the wavelength of de-Broglie wave is given by \[\lambda =\frac{h}{p}=\frac{h}{mv}\] \[=\frac{h}{\sqrt{2mK}}\]
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